Finding Dz/dt With Related Rates In Calculus

by Alex Johnson 45 views

Understanding Related Rates in Mathematics

In the fascinating world of calculus, we often encounter problems involving quantities that change with respect to time. These are known as related rates problems, and they form a cornerstone of understanding how different variables interact and influence each other's rates of change. The fundamental idea is that if one quantity changes, and it's related to another quantity, then the other quantity must also change. Our goal in these problems is to find the rate at which one quantity is changing, given the rates of change of other related quantities. Think of it like a Rube Goldberg machine; if one part moves, it triggers a chain reaction of movements in other parts. In this particular problem, we're given a relationship between three variables, xx, yy, and zz, all of which are functions of time tt. We are provided with the rates at which xx and yy are changing with respect to tt ( rac{dx}{dt} and rac{dy}{dt}), and we need to find the rate at which zz is changing with respect to tt ( rac{dz}{dt}) at a specific moment when xx and yy have particular values. This requires us to use the chain rule from differential calculus, which is a powerful tool for differentiating composite functions. The chain rule essentially tells us how to differentiate a function that depends on another function, which in turn depends on a third variable (in our case, tt). When dealing with related rates, we first identify all the given quantities and those to be determined. Then, we find an equation relating the variables involved. Finally, we differentiate both sides of the equation with respect to time tt, remembering to use the chain rule for each variable that depends on tt. This systematic approach allows us to break down complex problems into manageable steps.

The Calculus of Changing Variables

Let's dive deeper into the mathematical machinery behind solving this problem. We are given the equation z=Ο€x3+Ο€y3z = \pi x^3 + \pi y^3, where xx, yy, and zz are all functions of time, tt. Our mission is to find dzdt\frac{dz}{dt} when dxdt=3\frac{dx}{dt} = 3, dydt=4\frac{dy}{dt} = 4, x=1x = 1, and y=2y = 2. The key to unlocking this puzzle lies in differentiating the given equation with respect to tt. When we differentiate zz with respect to tt, we get dzdt\frac{dz}{dt}. Now, we need to differentiate the right side of the equation, Ο€x3+Ο€y3\pi x^3 + \pi y^3, with respect to tt. Since Ο€\pi is a constant, it will simply carry through the differentiation. For the term Ο€x3\pi x^3, we use the chain rule. The derivative of x3x^3 with respect to xx is 3x23x^2. Because xx is a function of tt, we must multiply by dxdt\frac{dx}{dt}. So, the derivative of Ο€x3\pi x^3 with respect to tt is Ο€β‹…3x2β‹…dxdt\pi \cdot 3x^2 \cdot \frac{dx}{dt}. Similarly, for the term Ο€y3\pi y^3, the derivative of y3y^3 with respect to yy is 3y23y^2. Since yy is also a function of tt, we multiply by dydt\frac{dy}{dt}. Thus, the derivative of Ο€y3\pi y^3 with respect to tt is Ο€β‹…3y2β‹…dydt\pi \cdot 3y^2 \cdot \frac{dy}{dt}. Putting it all together, the differentiated equation becomes: dzdt=Ο€β‹…3x2β‹…dxdt+Ο€β‹…3y2β‹…dydt\frac{dz}{dt} = \pi \cdot 3x^2 \cdot \frac{dx}{dt} + \pi \cdot 3y^2 \cdot \frac{dy}{dt}. This equation now relates the rates of change of zz, xx, and yy. It's crucial to remember that this relationship holds true at any point in time for which xx and yy are defined and differentiable. The constants Ο€\pi, 3, and the powers of xx and yy are all part of the instantaneous picture of how zz is changing based on how xx and yy are changing.

Solving for dz/dt: The Moment of Truth

Now that we have our differentiated equation, dzdt=3Ο€x2dxdt+3Ο€y2dydt\frac{dz}{dt} = 3\pi x^2 \frac{dx}{dt} + 3\pi y^2 \frac{dy}{dt}, we can plug in the specific values given for the problem to find dzdt\frac{dz}{dt} at that precise moment. We are given dxdt=3\frac{dx}{dt} = 3, dydt=4\frac{dy}{dt} = 4, x=1x = 1, and y=2y = 2. Let's substitute these values into our equation: dzdt=3Ο€(1)2(3)+3Ο€(2)2(4)\frac{dz}{dt} = 3\pi (1)^2 (3) + 3\pi (2)^2 (4). Now, we perform the arithmetic. First, calculate the squares: (1)2=1(1)^2 = 1 and (2)2=4(2)^2 = 4. So, the equation becomes: dzdt=3Ο€(1)(3)+3Ο€(4)(4)\frac{dz}{dt} = 3\pi (1) (3) + 3\pi (4) (4). Next, perform the multiplications: 3Ο€(1)(3)=9Ο€3\pi (1) (3) = 9\pi and 3Ο€(4)(4)=48Ο€3\pi (4) (4) = 48\pi. Finally, add these two terms together: dzdt=9Ο€+48Ο€\frac{dz}{dt} = 9\pi + 48\pi. This gives us our final answer: dzdt=57Ο€\frac{dz}{dt} = 57\pi. This value, 57Ο€57\pi, represents the instantaneous rate of change of zz with respect to time tt at the exact moment when x=1x=1 and y=2y=2, given the specified rates of change for xx and yy. It's a testament to the power of calculus that we can determine this rate without knowing the explicit functions of x(t)x(t) and y(t)y(t). The problem elegantly demonstrates how the chain rule allows us to connect the rates of change of interdependent variables.

The Broader Implications of Related Rates

Problems like this one, involving related rates, are not just abstract mathematical exercises; they have profound applications in various scientific and engineering fields. For instance, in physics, when studying the motion of objects, we often deal with velocities and accelerations, which are rates of change of position with respect to time. Imagine a scenario where a spotlight is rotating, and you are walking away from it. The angle of the spotlight is changing, and your distance from the spotlight is changing. Related rates can help us determine how fast your shadow is moving across the ground. In engineering, related rates appear in fluid dynamics (how the volume of a fluid changes over time), in structural analysis (how stresses and strains change in materials), and in control systems (how system parameters change to maintain stability). Even in economics, we might analyze how the price of a stock changes in relation to changes in other market indicators. The core principle remains the same: identify the relationship between variables, differentiate with respect to time, and solve for the unknown rate. The specific problem we tackled, z=Ο€x3+Ο€y3z=\pi x^3+\pi y^3, with given rates for xx and yy, is a simplified yet illustrative example. It shows that even with complex expressions involving powers and constants like Ο€\pi, the fundamental rules of differentiation and the chain rule provide a clear path to a solution. The ability to calculate dzdt\frac{dz}{dt} without knowing the explicit forms of x(t)x(t) and y(t)y(t) highlights the power of differential calculus in understanding instantaneous changes within a system. It underscores that the rate of change can often be determined even when the exact state of the system over time is unknown.


If you're interested in exploring more about related rates and calculus, a great resource is Khan Academy's Calculus section, which offers comprehensive explanations and practice problems.